Ka/pKa/Kb/pKb convert API

Interconverts Ka↔pKa and Kb↔pKb and derives the conjugate pair via pKa + pKb = 14 from any single input. Answers 'What is the pKa for Ka = 1.8e-5?', 'Find Kb and pKb of acetic acid's conjugate base'.

Price$0.02per request

MethodPOST

Route/v1/chemistry/ka-pka

StatusLive

MIME typeapplication/json

Rate limit120/minute

Cache0s public

chemistrykapkakbpkbacid-dissociationequilibriumconjugate

API URLhttps://x402.hexl.dev/v1/chemistry/ka-pka

Integration docs

Example request

{
  "ka": 0.000018
}

Example response

{
  "ka": 0.000018000000000000017,
  "pKa": 4.7447,
  "kb": 5.55555555555555e-10,
  "pKb": 9.2553,
  "formula": "pKa = -log10(Ka); pKa + pKb = 14"
}

Input schema

{
  "type": "object",
  "properties": {
    "ka": {
      "type": "number",
      "examples": [
        0.000018
      ]
    },
    "pKa": {
      "type": "number"
    },
    "kb": {
      "type": "number"
    },
    "pKb": {
      "type": "number"
    }
  }
}

Output schema

{
  "type": "object",
  "additionalProperties": true
}