Chemistry
Empirical formula from % API
Derives the empirical formula from percent (or mass) composition by mole-ratio normalisation and small-integer rounding, plus the molecular formula when a molecular mass is given. Answers 'What is the empirical formula of 40% C, 6.7% H, 53.3% O?', 'molecular formula of glucose from composition'.
Price$0.06per request
MethodPOST
Route/v1/chemistry/empirical-formula
StatusLive
MIME typeapplication/json
Rate limit120/minute
Cache0s public
chemistryempirical-formulamolecular-formulacompositionmole-ratiostoichiometrypercentanalysis
API URL
Integration docshttps://x402.hexl.dev/v1/chemistry/empirical-formulaExample request
{
"percentages": {
"C": 40,
"H": 6.7,
"O": 53.3
},
"molecularMass": 180
}Example response
{
"empiricalFormula": "CH2O",
"empiricalSubscripts": {
"C": 1,
"H": 2,
"O": 1
},
"empiricalMolarMass": 30.026,
"moleRatios": {
"C": 1,
"H": 1.9959,
"O": 1.0004
},
"molecularMultiple": 6,
"molecularFormula": "C6H12O6"
}Input schema
{
"type": "object",
"required": [
"percentages"
],
"properties": {
"percentages": {
"type": "object",
"examples": [
{
"C": 40,
"H": 6.7,
"O": 53.3
}
]
},
"molecularMass": {
"type": "number",
"examples": [
180
]
}
}
}Output schema
{
"type": "object",
"additionalProperties": true
}